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Click here:point_up_2:to get an answer to your question :writing_hand:abcd is a parallelogram p isa point on side bc such that dp produced meets
ABCD is a quadrilateral and AP and DP are bisectors of angle A and ap dp Click here:point_up_2:to get an answer to your question :writing_hand:abcd is a parallelogram p isa point on side bc such that dp produced meets ap challan payment Given: Seg AC and seg BD intersect each other in point P and AP CP BP DP AP CP = BP DP To prove: ∆ABP ~ ∆CDP Proof: In ∆ABP and ∆CDP,
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